Any vehicle encounters 5 types of resistance.
Inertia resistance
Grade resistance
Rolling resistance
curve resistance
Aerodynamic resistance
For a 3500lb boat/trailer combo…
Assume the following scenario…
Maintaining 50mph
Climbing a 6% grade
Rolling on poor pavement
While negotiating a typical highway curve at 50 mph
With a 50 square foot cross section
Inertia resistance force = 0 since speed is constant
Grade resistance force=weightgrade=35006%=210lb force
Rolling resistance at 50mph on broken pavement=51lb/ton =51*3500/2000=89lb force
Curve resistance for degree of curve of 5 at 50mph = 18lb
Aerodynamic drag force for typical automotive cross sections = 0.0006areamph^2
=.0006502500=75lb
So the total tractive effort required to maintain 50mph under this relatively harsh combination of resistance is 392lb force.
At 50 MPH (73.3 ft/sec), your vehicle must spare 392*73.3/550=52 horsepower above and beyond what it’s using to drive the car, which is:
Weight =110% of curb weight =1.1*2194=2413lb
frontal area =23.7 sq ft
Grade resistance = 24136%=145 lb force
Rolling resistance =51lb/ton=512413/2000=62lb force
Curve resistance=18 lb
Aerodynamic drag=.000623.750^2=36lb
For a total of 260 lb force (using unrounded intermediate values), which at 50 mph requires 260*73.3/550=35 horsepower, for a total of 87 horsepower.
This car’s engine only makes 108 brake horsepower, and you’d be lucky to get 70% of that to the ground with the pedal to the metal, which is 75.6 horsepower.
All other issues aside, pulling such a trailer would require more than 100% of available output under the conditions above. It’s one thing to say something is a bad idea, but in this particular case, the numbers say it’s not going to happen. You need at least 13% more muscle before you can even do it holding the pedal to the floor.
Unfortunately, it appears that this combination will kill your car in a fast hurry.