With all respect due, weekend, your explanation was just viewed by someone who can barely add & multiply, let alone comprehend what you postulated.
What I did glean from it, and what I know:
Air, as we know it, becomes more dense at lower temperatures. the air at 0degF is more dense than the air at 100degF.
Secondly, the common rule of thumb stated by everyone from the garage down the street, to tire websites, to Consumer Reports, is that cold tire pressure - that pressure before the car is driven - changes “approximately 1psi(6.8kPa) per 10degF(5.5C) change in ambient temperature”. It’s actually about 0.89psi per 10degF, but that’s splitting hairs.
It is ASSUMED that a ten degree F change in temperature, whether that occurs at 30F or 80F, approximates a 1psi change in cold tire pressure.
So given all of that, are you suggesting that the actual pressure loss, given the higher density of air at 0F, is greater if the temperature drops from 0F to -20 than when the temperature drops from 100F to 80F?
IE, using the age-old rule of thumb, 1psi per 10F, results in a 2psi pressure loss from 100 to 80 deg F.
So what, in simple terms for a mathematically-challenged fool like myself, would be the pressure loss, in PSI, for a temperature dip from 0F to -20?