# Oh Fer Math Puzzler

**URL:** <https://community.cartalk.com/t/oh-fer-math-puzzler/31196>\
**Category:** Maintenance/Repairs\
**Created:** [May 30, 2009, 8:01pm UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196 "2009-05-30T20:01:48Z")\
**Posts on this page:** 11\
**Page:** 1

<div class="post-metadata">

**Author:** ![Caller\_X](https://avatars.discourse-cdn.com/v4/letter/c/8797f3/32.png) [@Caller\_X](https://community.cartalk.com/u/Caller_X)\
**Post date:** [May 30, 2009, 8:01pm UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/1 "2009-05-30T20:01:48Z")

</div>

Only one answer, brother with more treble in his channel than the other brother?  
  
  
  
 5^2 + 4mod3 =26

---

<div class="post-metadata">

**Author:** ![oldschool](https://avatars.discourse-cdn.com/v4/letter/o/e19adc/32.png) [@oldschool](https://community.cartalk.com/u/oldschool)\
**Post date:** [May 30, 2009, 10:26pm UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/2 "2009-05-30T22:26:33Z")

</div>

Can you expand on your equation,you will get more response. What does the “mod” in 4mod3 represent? I guess mod3 means base 3?

---

<div class="post-metadata">

**Author:** ![cigroller](https://avatars.discourse-cdn.com/v4/letter/c/c68b51/32.png) [@cigroller](https://community.cartalk.com/u/cigroller)\
**Post date:** [May 30, 2009, 10:34pm UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/3 "2009-05-30T22:34:44Z")

</div>

(5 + 6 + SQRT(4)) x 2 = 26

---

<div class="post-metadata">

**Author:** ![jtsanders](https://avatars.discourse-cdn.com/v4/letter/j/c2a13f/32.png) [@jtsanders](https://community.cartalk.com/u/jtsanders)\
**Post date:** [May 30, 2009, 10:41pm UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/4 "2009-05-30T22:41:52Z")

</div>

mod means modulo. It means the remainder after the first number is divided by the second. 4mod3 is the remainder after dividing 4 by 3, e.g 1.

---

<div class="post-metadata">

**Author:** ![mcparadise](https://sea1.discourse-cdn.com/cartalk/user_avatar/community.cartalk.com/mcparadise/32/32_2.png) [@mcparadise](https://community.cartalk.com/u/mcparadise)\
**Post date:** [May 30, 2009, 10:48pm UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/5 "2009-05-30T22:48:51Z")

</div>

Sorry, but the answer is 42.

It’s the answer to life, the universe, and everything.

---

<div class="post-metadata">

**Author:** ![oldschool](https://avatars.discourse-cdn.com/v4/letter/o/e19adc/32.png) [@oldschool](https://community.cartalk.com/u/oldschool)\
**Post date:** [May 31, 2009, 2:40am UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/6 "2009-05-31T02:40:51Z")

</div>

I get 43,at least my TI 83 gets 43.

---

<div class="post-metadata">

**Author:** ![edb1961](https://sea1.discourse-cdn.com/cartalk/user_avatar/community.cartalk.com/edb1961/32/122_2.png) [@edb1961](https://community.cartalk.com/u/edb1961)\
**Post date:** [May 31, 2009, 4:27am UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/7 "2009-05-31T04:27:49Z")

</div>

Yes, but what is the question?

---

<div class="post-metadata">

**Author:** ![Gary123](https://avatars.discourse-cdn.com/v4/letter/g/c37758/32.png) [@Gary123](https://community.cartalk.com/u/Gary123)\
**Post date:** [May 31, 2009, 5:00am UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/8 "2009-05-31T05:00:59Z")

</div>

How do you get an answer of 42 or 43.  
(5^2)+(4 mod 3) … 5 to the power of 2 is 25 and 4mod3 is 1 … add them together for an answer of 26.  
You could insert brackets to change the order so that the equation reads  
5^(2+(4 mod 3)) … then the answer is 125.

Are you sure that this is the answer to everything. I thought the answer was an engine that got 200 MPG and developed 600 HP.

---

<div class="post-metadata">

**Author:** ![oldschool](https://avatars.discourse-cdn.com/v4/letter/o/e19adc/32.png) [@oldschool](https://community.cartalk.com/u/oldschool)\
**Post date:** [May 31, 2009, 6:14am UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/9 "2009-05-31T06:14:08Z")

</div>

I calculated (5+6+2)(2) and got 26 this time. The first time I did 4^2 instead of sqrt4. I don’t know how to work the “mod” problems. At what level is this “mod” concept put forth? I just finished Algebra 151 (next is pre-calcus) last semester and have not yet been introduced to the process. And yes what is the question? Really I have never heard of the “mod” concept,probably should have in 3rd grade.

---

<div class="post-metadata">

**Author:** ![Howard\_Abts](https://avatars.discourse-cdn.com/v4/letter/h/54ee81/32.png) [@Howard\_Abts](https://community.cartalk.com/u/Howard_Abts)\
**Post date:** [June 1, 2009, 2:17pm UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/10 "2009-06-01T14:17:37Z")

</div>

I LOVE it when Ray says, “There’s only one answer.” And I found another ten:

24+5-3  
23+5- the square root of 4 (Keyboard here doesn’t do everything I wish it did.)  
52 divided by (square root of 4)base 3  
5x3!-([square root of 4]+2)  
23 base 5 x square root of 4  
4!+(2 base 35)  
4!+(2 base 53)  
4x3!+(2 base 5)  
4x(3 base five !)+2  
(4 base 5)x3!+2

Any more?

---

<div class="post-metadata">

**Author:** ![vtcodger2](https://avatars.discourse-cdn.com/v4/letter/v/e68b1a/32.png) [@vtcodger2](https://community.cartalk.com/u/vtcodger2)\
**Post date:** [June 1, 2009, 2:28pm UTC](https://community.cartalk.com/t/oh-fer-math-puzzler/31196/11 "2009-06-01T14:28:01Z")

</div>

(25+4-3)/1 = 26 probably

and therefore, probably

(25+4-3)\*1 = 26 and  
(25+4-3)^1 = 26 as well
